This section covers transformations of functions of the form \(y = f(x)\) to \(y = Af(n(x+b)) + c\), where \(A, n, b,\) and \(c\) are real numbers, and \(A, n eq 0\). We’ll also explore the inverse transformation.
This equation combines several transformations. Let’s break down each parameter:
A: Vertical dilation (stretch/compression) and/or reflection in the x-axis.
n: Horizontal dilation (stretch/compression) and/or reflection in the y-axis.
b: Horizontal translation.
c: Vertical translation.
It is crucial to apply transformations in the correct order. A recommended order is:
We can represent the transformation using mapping notation:
\((x, y) \rightarrow (\frac{x}{n} - b, Ay + c)\)
This notation shows how a point \((x, y)\) on the original graph \(y = f(x)\) is mapped to a new point \((\frac{x}{n} - b, Ay + c)\) on the transformed graph \(y = Af(n(x+b)) + c\).
To find the inverse transformation, we need to reverse the process. If the original transformation is:
\(y = Af(n(x+b)) + c\)
Then the inverse transformation can be found as follows:
Finally, swap \(x\) and \(y\) to express the inverse function in terms of x:
\(y = \frac{1}{n}f^{-1}(\frac{x-c}{A}) - b\)
Or, using mapping notation, the inverse transformation is:
\((x, y) \rightarrow (\frac{x - c}{A}, ny + b)\)
| Function | Transformation | Effect |
|---|---|---|
| \(y = x^2\) | \(y = -(x+2)^2 - 1\) | Reflected in x-axis, translated 2 units left, 1 unit down |
| \(y = \sqrt{x}\) | \(y = 2\sqrt{x-3}\) | Vertical stretch by 2, translated 3 units right |
| \(y = \frac{1}{x}\) | \(y = \frac{3}{2x} + 4\) | Vertical stretch by 3, horizontal compression by \(\frac{1}{2}\), translated 4 units up |
| \(y = e^x\) | \(y = e^{-x} - 2\) | Reflected in y-axis, translated 2 units down |
| \(y = \sin(x)\) | \(y = 3\sin(2x)\) | Vertical stretch by 3, horizontal compression by \(\frac{1}{2}\) |
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